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1323111325001 is a prime number
BaseRepresentation
bin10011010000001111100…
…101001001110101001001
311200111011220101102000012
4103100033211021311021
5133134212444400001
62451455015321305
7164406634461554
oct23201745116511
94614156342005
101323111325001
11470145938794
12194517380235
13979cc263a8b
1448078b7569b
152463cdc52bb
hex1340f949d49

1323111325001 has 2 divisors, whose sum is σ = 1323111325002. Its totient is φ = 1323111325000.

The previous prime is 1323111324991. The next prime is 1323111325037. The reversal of 1323111325001 is 1005231113231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1211188291600 + 111923033401 = 1100540^2 + 334549^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323111325001 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1323111327001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661555662500 + 661555662501.

It is an arithmetic number, because the mean of its divisors is an integer number (661555662501).

Almost surely, 21323111325001 is an apocalyptic number.

It is an amenable number.

1323111325001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323111325001 is an equidigital number, since it uses as much as digits as its factorization.

1323111325001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 1323111325001 its reverse (1005231113231), we get a palindrome (2328342438232).

The spelling of 1323111325001 in words is "one trillion, three hundred twenty-three billion, one hundred eleven million, three hundred twenty-five thousand, one".