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13231141243 = 54124456823
BaseRepresentation
bin11000101001010001…
…10011000101111011
31021011002201121122021
430110220303011323
5204044133004433
610024525135311
7645610562545
oct142450630573
937132647567
1013231141243
11567a6a8281
1226930ba537
13132b240578
148d7336695
155268ad22d
hex314a3317b

13231141243 has 4 divisors (see below), whose sum is σ = 13255598608. Its totient is φ = 13206683880.

The previous prime is 13231141223. The next prime is 13231141249. The reversal of 13231141243 is 34214113231.

13231141243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13231141243 - 25 = 13231141211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13231141249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12227871 + ... + 12228952.

It is an arithmetic number, because the mean of its divisors is an integer number (3313899652).

Almost surely, 213231141243 is an apocalyptic number.

13231141243 is a deficient number, since it is larger than the sum of its proper divisors (24457365).

13231141243 is an equidigital number, since it uses as much as digits as its factorization.

13231141243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24457364.

The product of its digits is 1728, while the sum is 25.

Adding to 13231141243 its reverse (34214113231), we get a palindrome (47445254474).

The spelling of 13231141243 in words is "thirteen billion, two hundred thirty-one million, one hundred forty-one thousand, two hundred forty-three".

Divisors: 1 541 24456823 13231141243