Base | Representation |
---|---|
bin | 1100000010001001111011… |
… | …0010001101011011001001 |
3 | 1201211212221111220112012111 |
4 | 3000202132302031123021 |
5 | 3213234410241441433 |
6 | 44050151254542321 |
7 | 2533630362564115 |
oct | 300423662153311 |
9 | 51755844815174 |
10 | 13231163233993 |
11 | 4241339789931 |
12 | 15983559679a1 |
13 | 74c902360303 |
14 | 33a56ac30745 |
15 | 17e28d90bdcd |
hex | c089ec8d6c9 |
13231163233993 has 2 divisors, whose sum is σ = 13231163233994. Its totient is φ = 13231163233992.
The previous prime is 13231163233927. The next prime is 13231163234017. The reversal of 13231163233993 is 39933236113231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6910605212809 + 6320558021184 = 2628803^2 + 2514072^2 .
It is a cyclic number.
It is not a de Polignac number, because 13231163233993 - 233 = 13222573299401 is a prime.
It is not a weakly prime, because it can be changed into another prime (13231163233193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615581616996 + 6615581616997.
It is an arithmetic number, because the mean of its divisors is an integer number (6615581616997).
Almost surely, 213231163233993 is an apocalyptic number.
It is an amenable number.
13231163233993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231163233993 is an equidigital number, since it uses as much as digits as its factorization.
13231163233993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1417176, while the sum is 49.
The spelling of 13231163233993 in words is "thirteen trillion, two hundred thirty-one billion, one hundred sixty-three million, two hundred thirty-three thousand, nine hundred ninety-three".
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