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1323121000213 is a prime number
BaseRepresentation
bin10011010000010000001…
…010000011111100010101
311200111012120120221220101
4103100100022003330111
5133134222434001323
62451500002534101
7164410112636305
oct23202012037425
94614176527811
101323121000213
11470150346931
1219451a667331
1397a0127085c
144807a173605
152463db86dad
hex13410283f15

1323121000213 has 2 divisors, whose sum is σ = 1323121000214. Its totient is φ = 1323121000212.

The previous prime is 1323121000181. The next prime is 1323121000273. The reversal of 1323121000213 is 3120001213231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1299834850609 + 23286149604 = 1140103^2 + 152598^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323121000213 - 25 = 1323121000181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323121000273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661560500106 + 661560500107.

It is an arithmetic number, because the mean of its divisors is an integer number (661560500107).

Almost surely, 21323121000213 is an apocalyptic number.

It is an amenable number.

1323121000213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323121000213 is an equidigital number, since it uses as much as digits as its factorization.

1323121000213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1323121000213 its reverse (3120001213231), we get a palindrome (4443122213444).

The spelling of 1323121000213 in words is "one trillion, three hundred twenty-three billion, one hundred twenty-one million, two hundred thirteen", and thus it is an aban number.