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1323121310249 is a prime number
BaseRepresentation
bin10011010000010000001…
…011001111101000101001
311200111012121011201012012
4103100100023033220221
5133134223023411444
62451500013325305
7164410115400224
oct23202013175051
94614177151165
101323121310249
11470150538862
1219451a796835
1397a0134b9cb
144807a2145bb
152463dbe8b9e
hex134102cfa29

1323121310249 has 2 divisors, whose sum is σ = 1323121310250. Its totient is φ = 1323121310248.

The previous prime is 1323121310209. The next prime is 1323121310257. The reversal of 1323121310249 is 9420131213231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 689178908224 + 633942402025 = 830168^2 + 796205^2 .

It is an emirp because it is prime and its reverse (9420131213231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323121310249 - 224 = 1323104533033 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323121310209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661560655124 + 661560655125.

It is an arithmetic number, because the mean of its divisors is an integer number (661560655125).

Almost surely, 21323121310249 is an apocalyptic number.

It is an amenable number.

1323121310249 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323121310249 is an equidigital number, since it uses as much as digits as its factorization.

1323121310249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 1323121310249 in words is "one trillion, three hundred twenty-three billion, one hundred twenty-one million, three hundred ten thousand, two hundred forty-nine".