Base | Representation |
---|---|
bin | 111101100111001101… |
… | …1000101100101000101 |
3 | 110122112001210111120011 |
4 | 1323032123011211011 |
5 | 4131433412213432 |
6 | 140441114110221 |
7 | 12362551236241 |
oct | 1731633054505 |
9 | 418461714504 |
10 | 132312226117 |
11 | 51127890905 |
12 | 2178711b371 |
13 | c627c3a876 |
14 | 65925db421 |
15 | 3695d4c847 |
hex | 1ece6c5945 |
132312226117 has 2 divisors, whose sum is σ = 132312226118. Its totient is φ = 132312226116.
The previous prime is 132312226103. The next prime is 132312226121. The reversal of 132312226117 is 711622213231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112765669636 + 19546556481 = 335806^2 + 139809^2 .
It is a cyclic number.
It is not a de Polignac number, because 132312226117 - 219 = 132311701829 is a prime.
It is a super-2 number, since 2×1323122261172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132312226157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156113058 + 66156113059.
It is an arithmetic number, because the mean of its divisors is an integer number (66156113059).
Almost surely, 2132312226117 is an apocalyptic number.
It is an amenable number.
132312226117 is a deficient number, since it is larger than the sum of its proper divisors (1).
132312226117 is an equidigital number, since it uses as much as digits as its factorization.
132312226117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6048, while the sum is 31.
Adding to 132312226117 its reverse (711622213231), we get a palindrome (843934439348).
The spelling of 132312226117 in words is "one hundred thirty-two billion, three hundred twelve million, two hundred twenty-six thousand, one hundred seventeen".
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