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132312301199977 is a prime number
BaseRepresentation
bin11110000101011001011011…
…101101100110001001101001
3122100110221011202122212112011
4132011121123231212021221
5114320301043101344402
61145223233153315521
736604151111464033
oct3605313355461151
9570427152585464
10132312301199977
113918237171a988
1212a0b015b65ba1
1358a9cc530a9c2
142495d417b4c53
151046b2eb4eed7
hex78565bb66269

132312301199977 has 2 divisors, whose sum is σ = 132312301199978. Its totient is φ = 132312301199976.

The previous prime is 132312301199921. The next prime is 132312301200151. The reversal of 132312301199977 is 779991103213231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125692440477696 + 6619860722281 = 11211264^2 + 2572909^2 .

It is a cyclic number.

It is not a de Polignac number, because 132312301199977 - 27 = 132312301199849 is a prime.

It is not a weakly prime, because it can be changed into another prime (132312301199077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156150599988 + 66156150599989.

It is an arithmetic number, because the mean of its divisors is an integer number (66156150599989).

Almost surely, 2132312301199977 is an apocalyptic number.

It is an amenable number.

132312301199977 is a deficient number, since it is larger than the sum of its proper divisors (1).

132312301199977 is an equidigital number, since it uses as much as digits as its factorization.

132312301199977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3857868, while the sum is 58.

The spelling of 132312301199977 in words is "one hundred thirty-two trillion, three hundred twelve billion, three hundred one million, one hundred ninety-nine thousand, nine hundred seventy-seven".