Base | Representation |
---|---|
bin | 11110000101011001011011… |
… | …101101100110001100010111 |
3 | 122100110221011202122212202121 |
4 | 132011121123231212030113 |
5 | 114320301043101401101 |
6 | 1145223233153320411 |
7 | 36604151111464402 |
oct | 3605313355461427 |
9 | 570427152585677 |
10 | 132312301200151 |
11 | 39182371720026 |
12 | 12a0b015b66107 |
13 | 58a9cc530aac7 |
14 | 2495d417b4d39 |
15 | 1046b2eb500a1 |
hex | 78565bb66317 |
132312301200151 has 2 divisors, whose sum is σ = 132312301200152. Its totient is φ = 132312301200150.
The previous prime is 132312301199977. The next prime is 132312301200169. The reversal of 132312301200151 is 151002103213231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132312301200151 - 233 = 132303711265559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132312301260151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156150600075 + 66156150600076.
It is an arithmetic number, because the mean of its divisors is an integer number (66156150600076).
Almost surely, 2132312301200151 is an apocalyptic number.
132312301200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
132312301200151 is an equidigital number, since it uses as much as digits as its factorization.
132312301200151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 132312301200151 its reverse (151002103213231), we get a palindrome (283314404413382).
The spelling of 132312301200151 in words is "one hundred thirty-two trillion, three hundred twelve billion, three hundred one million, two hundred thousand, one hundred fifty-one".
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