Base | Representation |
---|---|
bin | 11110000101011001100111… |
… | …100101000110100011110111 |
3 | 122100110221200122022012102221 |
4 | 132011121213211012203313 |
5 | 114320302000034100043 |
6 | 1145223305024543211 |
7 | 36604156050012451 |
oct | 3605314745064367 |
9 | 570427618265387 |
10 | 132312500300023 |
11 | 3918246404877a |
12 | 12a0b070781b07 |
13 | 58aa02763b494 |
14 | 2495d600012d1 |
15 | 1046b4237c8ed |
hex | 7856679468f7 |
132312500300023 has 4 divisors (see below), whose sum is σ = 132312523703760. Its totient is φ = 132312476896288.
The previous prime is 132312500300021. The next prime is 132312500300033. The reversal of 132312500300023 is 320003005213231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132312500300023 - 21 = 132312500300021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132312500300021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2626383 + ... + 16477951.
It is an arithmetic number, because the mean of its divisors is an integer number (33078130925940).
Almost surely, 2132312500300023 is an apocalyptic number.
132312500300023 is a deficient number, since it is larger than the sum of its proper divisors (23403737).
132312500300023 is an equidigital number, since it uses as much as digits as its factorization.
132312500300023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23403736.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 132312500300023 its reverse (320003005213231), we get a palindrome (452315505513254).
The spelling of 132312500300023 in words is "one hundred thirty-two trillion, three hundred twelve billion, five hundred million, three hundred thousand, twenty-three".
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