Base | Representation |
---|---|
bin | 11000101001010010… |
… | …11001111000000101 |
3 | 1021011010000200112220 |
4 | 30110221121320011 |
5 | 204044203100401 |
6 | 10024532402553 |
7 | 645612123645 |
oct | 142451317005 |
9 | 37133020486 |
10 | 13231300101 |
11 | 567a7a6668 |
12 | 2693176459 |
13 | 132b297976 |
14 | 8d7378525 |
15 | 5268e0336 |
hex | 314a59e05 |
13231300101 has 4 divisors (see below), whose sum is σ = 17641733472. Its totient is φ = 8820866732.
The previous prime is 13231300067. The next prime is 13231300109. The reversal of 13231300101 is 10100313231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13231300101 - 210 = 13231299077 is a prime.
It is a super-2 number, since 2×132313001012 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13231300109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2205216681 + ... + 2205216686.
It is an arithmetic number, because the mean of its divisors is an integer number (4410433368).
Almost surely, 213231300101 is an apocalyptic number.
It is an amenable number.
13231300101 is a deficient number, since it is larger than the sum of its proper divisors (4410433371).
13231300101 is an equidigital number, since it uses as much as digits as its factorization.
13231300101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4410433370.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13231300101 its reverse (10100313231), we get a palindrome (23331613332).
The spelling of 13231300101 in words is "thirteen billion, two hundred thirty-one million, three hundred thousand, one hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •