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132313100221147 is a prime number
BaseRepresentation
bin11110000101011010001011…
…010101100111101011011011
3122100111000020110011100111211
4132011122023111213223123
5114320304212124034042
61145223444335203551
736604206653162566
oct3605321325475333
9570430213140454
10132313100221147
113918274175235a
1212a0b1b96765b7
1358aa0c1a0a1b1
142495db99674dd
151046b79d82017
hex78568b567adb

132313100221147 has 2 divisors, whose sum is σ = 132313100221148. Its totient is φ = 132313100221146.

The previous prime is 132313100221061. The next prime is 132313100221397. The reversal of 132313100221147 is 741122001313231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132313100221147 - 27 = 132313100221019 is a prime.

It is not a weakly prime, because it can be changed into another prime (132313100221747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156550110573 + 66156550110574.

It is an arithmetic number, because the mean of its divisors is an integer number (66156550110574).

Almost surely, 2132313100221147 is an apocalyptic number.

132313100221147 is a deficient number, since it is larger than the sum of its proper divisors (1).

132313100221147 is an equidigital number, since it uses as much as digits as its factorization.

132313100221147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 132313100221147 its reverse (741122001313231), we get a palindrome (873435101534378).

The spelling of 132313100221147 in words is "one hundred thirty-two trillion, three hundred thirteen billion, one hundred million, two hundred twenty-one thousand, one hundred forty-seven".