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132313100221831 is a prime number
BaseRepresentation
bin11110000101011010001011…
…010101100111110110000111
3122100111000020110011101110011
4132011122023111213312013
5114320304212124044311
61145223444335211051
736604206653164564
oct3605321325476607
9570430213141404
10132313100221831
1139182741752921
1212a0b1b9676a87
1358aa0c1a0a5b9
142495db996786b
151046b79d82321
hex78568b567d87

132313100221831 has 2 divisors, whose sum is σ = 132313100221832. Its totient is φ = 132313100221830.

The previous prime is 132313100221801. The next prime is 132313100221873. The reversal of 132313100221831 is 138122001313231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132313100221831 - 213 = 132313100213639 is a prime.

It is a super-2 number, since 2×1323131002218312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132313100221793 and 132313100221802.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132313100221801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156550110915 + 66156550110916.

It is an arithmetic number, because the mean of its divisors is an integer number (66156550110916).

Almost surely, 2132313100221831 is an apocalyptic number.

132313100221831 is a deficient number, since it is larger than the sum of its proper divisors (1).

132313100221831 is an equidigital number, since it uses as much as digits as its factorization.

132313100221831 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 132313100221831 in words is "one hundred thirty-two trillion, three hundred thirteen billion, one hundred million, two hundred twenty-one thousand, eight hundred thirty-one".