Base | Representation |
---|---|
bin | 10011010000010000110… |
… | …000111110101011111101 |
3 | 11200111020021210021112111 |
4 | 103100100300332223331 |
5 | 133134233041433201 |
6 | 2451501005334021 |
7 | 164410265440066 |
oct | 23202060765375 |
9 | 4614207707474 |
10 | 1323131202301 |
11 | 470156084907 |
12 | 194521b67311 |
13 | 97a034033ac |
14 | 4807b66b56d |
15 | 2463e9eeb51 |
hex | 13410c3eafd |
1323131202301 has 4 divisors (see below), whose sum is σ = 1323193803552. Its totient is φ = 1323068601052.
The previous prime is 1323131202293. The next prime is 1323131202329. The reversal of 1323131202301 is 1032021313231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1323131202301 - 23 = 1323131202293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1323131202391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31268911 + ... + 31311196.
It is an arithmetic number, because the mean of its divisors is an integer number (330798450888).
Almost surely, 21323131202301 is an apocalyptic number.
It is an amenable number.
1323131202301 is a deficient number, since it is larger than the sum of its proper divisors (62601251).
1323131202301 is an equidigital number, since it uses as much as digits as its factorization.
1323131202301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62601250.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1323131202301 its reverse (1032021313231), we get a palindrome (2355152515532).
The spelling of 1323131202301 in words is "one trillion, three hundred twenty-three billion, one hundred thirty-one million, two hundred two thousand, three hundred one".
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