Base | Representation |
---|---|
bin | 1100000010001010100000… |
… | …1111111001100110011001 |
3 | 1201211220100120200021202112 |
4 | 3000202220033321212121 |
5 | 3213240221413341212 |
6 | 44050215130042105 |
7 | 2533634331303662 |
oct | 300425017714631 |
9 | 51756316607675 |
10 | 13231322012057 |
11 | 4241410377176 |
12 | 159839ab79335 |
13 | 74c929213826 |
14 | 33a583d62369 |
15 | 17e29c822422 |
hex | c08a83f9999 |
13231322012057 has 2 divisors, whose sum is σ = 13231322012058. Its totient is φ = 13231322012056.
The previous prime is 13231322012003. The next prime is 13231322012099. The reversal of 13231322012057 is 75021022313231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12802448958601 + 428873053456 = 3578051^2 + 654884^2 .
It is a cyclic number.
It is not a de Polignac number, because 13231322012057 - 212 = 13231322007961 is a prime.
It is not a weakly prime, because it can be changed into another prime (13231322012357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615661006028 + 6615661006029.
It is an arithmetic number, because the mean of its divisors is an integer number (6615661006029).
Almost surely, 213231322012057 is an apocalyptic number.
It is an amenable number.
13231322012057 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231322012057 is an equidigital number, since it uses as much as digits as its factorization.
13231322012057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 13231322012057 its reverse (75021022313231), we get a palindrome (88252344325288).
The spelling of 13231322012057 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty-two million, twelve thousand, fifty-seven".
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