Base | Representation |
---|---|
bin | 1100000010001010100000… |
… | …1111111001100101100011 |
3 | 1201211220100120200021200112 |
4 | 3000202220033321211203 |
5 | 3213240221413341003 |
6 | 44050215130041535 |
7 | 2533634331303554 |
oct | 300425017714543 |
9 | 51756316607615 |
10 | 13231322012003 |
11 | 4241410377127 |
12 | 159839ab792ab |
13 | 74c9292137b4 |
14 | 33a583d6232b |
15 | 17e29c8223d8 |
hex | c08a83f9963 |
13231322012003 has 2 divisors, whose sum is σ = 13231322012004. Its totient is φ = 13231322012002.
The previous prime is 13231322011997. The next prime is 13231322012057. The reversal of 13231322012003 is 30021022313231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13231322012003 - 24 = 13231322011987 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13231322012003.
It is not a weakly prime, because it can be changed into another prime (13231322018003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615661006001 + 6615661006002.
It is an arithmetic number, because the mean of its divisors is an integer number (6615661006002).
Almost surely, 213231322012003 is an apocalyptic number.
13231322012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231322012003 is an equidigital number, since it uses as much as digits as its factorization.
13231322012003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13231322012003 its reverse (30021022313231), we get a palindrome (43252344325234).
The spelling of 13231322012003 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty-two million, twelve thousand, three".
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