Base | Representation |
---|---|
bin | 11000101001010011… |
… | …10111011011110011 |
3 | 1021011010020211121222 |
4 | 30110221313123303 |
5 | 204044220434141 |
6 | 10024535135255 |
7 | 645613136633 |
oct | 142451673363 |
9 | 37133224558 |
10 | 13231421171 |
11 | 567a879621 |
12 | 269321452b |
13 | 132b30aac7 |
14 | 8d73aa6c3 |
15 | 52691614b |
hex | 314a776f3 |
13231421171 has 2 divisors, whose sum is σ = 13231421172. Its totient is φ = 13231421170.
The previous prime is 13231421107. The next prime is 13231421197. The reversal of 13231421171 is 17112413231.
It is an a-pointer prime, because the next prime (13231421197) can be obtained adding 13231421171 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13231421171 - 26 = 13231421107 is a prime.
It is a super-2 number, since 2×132314211712 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13231421171.
It is not a weakly prime, because it can be changed into another prime (13231121171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615710585 + 6615710586.
It is an arithmetic number, because the mean of its divisors is an integer number (6615710586).
Almost surely, 213231421171 is an apocalyptic number.
13231421171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231421171 is an equidigital number, since it uses as much as digits as its factorization.
13231421171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1008, while the sum is 26.
The spelling of 13231421171 in words is "thirteen billion, two hundred thirty-one million, four hundred twenty-one thousand, one hundred seventy-one".
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