Base | Representation |
---|---|
bin | 111101100111010001… |
… | …0101100111101011111 |
3 | 110122112012112220222201 |
4 | 1323032202230331133 |
5 | 4131434420104211 |
6 | 140441224552331 |
7 | 12362604222346 |
oct | 1731642547537 |
9 | 418465486881 |
10 | 132314222431 |
11 | 51128a24756 |
12 | 217879226a7 |
13 | c628489411 |
14 | 659299ab5d |
15 | 36960e40c1 |
hex | 1ece8acf5f |
132314222431 has 2 divisors, whose sum is σ = 132314222432. Its totient is φ = 132314222430.
The previous prime is 132314222419. The next prime is 132314222449. The reversal of 132314222431 is 134222413231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132314222431 - 211 = 132314220383 is a prime.
It is a super-2 number, since 2×1323142224312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132314222431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132314229431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157111215 + 66157111216.
It is an arithmetic number, because the mean of its divisors is an integer number (66157111216).
Almost surely, 2132314222431 is an apocalyptic number.
132314222431 is a deficient number, since it is larger than the sum of its proper divisors (1).
132314222431 is an equidigital number, since it uses as much as digits as its factorization.
132314222431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 28.
Adding to 132314222431 its reverse (134222413231), we get a palindrome (266536635662).
The spelling of 132314222431 in words is "one hundred thirty-two billion, three hundred fourteen million, two hundred twenty-two thousand, four hundred thirty-one".
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