Base | Representation |
---|---|
bin | 11110000101011100000101… |
… | …000110111110010101001010 |
3 | 122100111012111211101112112212 |
4 | 132011130011012332111022 |
5 | 114320322403124431442 |
6 | 1145224423155305122 |
7 | 36604311411216416 |
oct | 3605340506762512 |
9 | 570435454345485 |
10 | 132315143202122 |
11 | 3918359a986191 |
12 | 12a0b6898ab1a2 |
13 | 58aa359052b8a |
14 | 249613100dd46 |
15 | 1046c493d4a82 |
hex | 7857051be54a |
132315143202122 has 4 divisors (see below), whose sum is σ = 198472714803186. Its totient is φ = 66157571601060.
The previous prime is 132315143202061. The next prime is 132315143202149. The reversal of 132315143202122 is 221202341513231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 80557464095161 + 51757679106961 = 8975381^2 + 7194281^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33078785800529 + ... + 33078785800532.
Almost surely, 2132315143202122 is an apocalyptic number.
132315143202122 is a deficient number, since it is larger than the sum of its proper divisors (66157571601064).
132315143202122 is an equidigital number, since it uses as much as digits as its factorization.
132315143202122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66157571601063.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 132315143202122 its reverse (221202341513231), we get a palindrome (353517484715353).
The spelling of 132315143202122 in words is "one hundred thirty-two trillion, three hundred fifteen billion, one hundred forty-three million, two hundred two thousand, one hundred twenty-two".
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