Base | Representation |
---|---|
bin | 111101100111011100… |
… | …1001101100011101001 |
3 | 110122112121122201012111 |
4 | 1323032321031203221 |
5 | 4131442422414423 |
6 | 140441555242321 |
7 | 12363005326453 |
oct | 1731671154351 |
9 | 418477581174 |
10 | 132320123113 |
11 | 51131294a52 |
12 | 217898a93a1 |
13 | c629774149 |
14 | 65936952d3 |
15 | 36968ac60d |
hex | 1ecee4d8e9 |
132320123113 has 8 divisors (see below), whose sum is σ = 138233184768. Its totient is φ = 126420395904.
The previous prime is 132320123081. The next prime is 132320123123. The reversal of 132320123113 is 311321023231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132320123113 - 25 = 132320123081 is a prime.
It is a super-2 number, since 2×1323201231132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132320123123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3313320 + ... + 3353017.
It is an arithmetic number, because the mean of its divisors is an integer number (17279148096).
Almost surely, 2132320123113 is an apocalyptic number.
It is an amenable number.
132320123113 is a deficient number, since it is larger than the sum of its proper divisors (5913061655).
132320123113 is an equidigital number, since it uses as much as digits as its factorization.
132320123113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6667223.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 132320123113 its reverse (311321023231), we get a palindrome (443641146344).
The spelling of 132320123113 in words is "one hundred thirty-two billion, three hundred twenty million, one hundred twenty-three thousand, one hundred thirteen".
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