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1323203312339 is a prime number
BaseRepresentation
bin10011010000010101000…
…100000011101011010011
311200111102022110211220122
4103100111010003223103
5133134410021443324
62451512103100455
7164412132402326
oct23202504035323
94614368424818
101323203312339
11470192857187
1219454214172b
1397a1533045c
144808707c7bd
1524645ee5a5e
hex13415103ad3

1323203312339 has 2 divisors, whose sum is σ = 1323203312340. Its totient is φ = 1323203312338.

The previous prime is 1323203312311. The next prime is 1323203312363. The reversal of 1323203312339 is 9332133023231.

It is a strong prime.

It is an emirp because it is prime and its reverse (9332133023231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323203312339 - 232 = 1318908345043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1323203312299 and 1323203312308.

It is not a weakly prime, because it can be changed into another prime (1323203312369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661601656169 + 661601656170.

It is an arithmetic number, because the mean of its divisors is an integer number (661601656170).

Almost surely, 21323203312339 is an apocalyptic number.

1323203312339 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323203312339 is an equidigital number, since it uses as much as digits as its factorization.

1323203312339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52488, while the sum is 35.

The spelling of 1323203312339 in words is "one trillion, three hundred twenty-three billion, two hundred three million, three hundred twelve thousand, three hundred thirty-nine".