Base | Representation |
---|---|
bin | 11110000101100000111010… |
… | …011101101101010010000011 |
3 | 122100111200220112111220122211 |
4 | 132011200322131231102003 |
5 | 114320414020312240342 |
6 | 1145231042201442551 |
7 | 36604554132416353 |
oct | 3605407235552203 |
9 | 570450815456584 |
10 | 132320333321347 |
11 | 39185813637616 |
12 | 12a10697aa0457 |
13 | 58aa9a53b9542 |
14 | 24964a4440b63 |
15 | 1046e4ed92c17 |
hex | 78583a76d483 |
132320333321347 has 2 divisors, whose sum is σ = 132320333321348. Its totient is φ = 132320333321346.
The previous prime is 132320333321251. The next prime is 132320333321353. The reversal of 132320333321347 is 743123333023231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132320333321347 is a prime.
It is a super-2 number, since 2×1323203333213472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132320333321377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160166660673 + 66160166660674.
It is an arithmetic number, because the mean of its divisors is an integer number (66160166660674).
Almost surely, 2132320333321347 is an apocalyptic number.
132320333321347 is a deficient number, since it is larger than the sum of its proper divisors (1).
132320333321347 is an equidigital number, since it uses as much as digits as its factorization.
132320333321347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 489888, while the sum is 40.
Adding to 132320333321347 its reverse (743123333023231), we get a palindrome (875443666344578).
The spelling of 132320333321347 in words is "one hundred thirty-two trillion, three hundred twenty billion, three hundred thirty-three million, three hundred twenty-one thousand, three hundred forty-seven".
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