Base | Representation |
---|---|
bin | 111101100111011101… |
… | …0011100100101001001 |
3 | 110122112122021011012122 |
4 | 1323032322130211021 |
5 | 4131443013244133 |
6 | 140442010221025 |
7 | 12363011145233 |
oct | 1731672344511 |
9 | 418478234178 |
10 | 132320446793 |
11 | 51131496157 |
12 | 21789a24775 |
13 | c629858582 |
14 | 659373b253 |
15 | 3696923498 |
hex | 1ecee9c949 |
132320446793 has 2 divisors, whose sum is σ = 132320446794. Its totient is φ = 132320446792.
The previous prime is 132320446751. The next prime is 132320446837. The reversal of 132320446793 is 397644023231.
It is an a-pointer prime, because the next prime (132320446837) can be obtained adding 132320446793 to its sum of digits (44).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127214915584 + 5105531209 = 356672^2 + 71453^2 .
It is a cyclic number.
It is not a de Polignac number, because 132320446793 - 214 = 132320430409 is a prime.
It is not a weakly prime, because it can be changed into another prime (132320446393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160223396 + 66160223397.
It is an arithmetic number, because the mean of its divisors is an integer number (66160223397).
Almost surely, 2132320446793 is an apocalyptic number.
It is an amenable number.
132320446793 is a deficient number, since it is larger than the sum of its proper divisors (1).
132320446793 is an equidigital number, since it uses as much as digits as its factorization.
132320446793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 44.
The spelling of 132320446793 in words is "one hundred thirty-two billion, three hundred twenty million, four hundred forty-six thousand, seven hundred ninety-three".
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