1323210012181 has 2 divisors, whose sum is σ = 1323210012182. Its totient is φ = 1323210012180.

The previous prime is 1323210012169. The next prime is 1323210012217. The reversal of 1323210012181 is 1812100123231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1101731533956 + 221478478225 = 1049634^2 + 470615^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323210012181 - 2⁷ = 1323210012053 is a prime.

It is a super-2 number, since 2×1323210012181² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323210010181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661605006090 + 661605006091.

It is an arithmetic number, because the mean of its divisors is an integer number (661605006091).

Almost surely, 2^{1323210012181} is an apocalyptic number.

It is an amenable number.

1323210012181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323210012181 is an equidigital number, since it uses as much as digits as its factorization.

1323210012181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

The spelling of 1323210012181 in words is "one trillion, three hundred twenty-three billion, two hundred ten million, twelve thousand, one hundred eighty-one".