Base | Representation |
---|---|
bin | 111101100111011110… |
… | …0111111000010001111 |
3 | 110122112200111221222121 |
4 | 1323032330333002033 |
5 | 4131443201042312 |
6 | 140442032353411 |
7 | 12363016616224 |
oct | 1731674770217 |
9 | 418480457877 |
10 | 132321112207 |
11 | 51131900089 |
12 | 2178a0a5867 |
13 | c629a2c3cb |
14 | 659387194b |
15 | 3696a05707 |
hex | 1ecef3f08f |
132321112207 has 4 divisors (see below), whose sum is σ = 132337134160. Its totient is φ = 132305090256.
The previous prime is 132321112201. The next prime is 132321112247. The reversal of 132321112207 is 702211123231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 702211123231 = 2579 ⋅272280389.
It is a cyclic number.
It is not a de Polignac number, because 132321112207 - 23 = 132321112199 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132321112201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7998582 + ... + 8015107.
It is an arithmetic number, because the mean of its divisors is an integer number (33084283540).
Almost surely, 2132321112207 is an apocalyptic number.
132321112207 is a deficient number, since it is larger than the sum of its proper divisors (16021953).
132321112207 is an equidigital number, since it uses as much as digits as its factorization.
132321112207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16021952.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 132321112207 its reverse (702211123231), we get a palindrome (834532235438).
The spelling of 132321112207 in words is "one hundred thirty-two billion, three hundred twenty-one million, one hundred twelve thousand, two hundred seven".
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