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132321112207 = 826316013689
BaseRepresentation
bin111101100111011110…
…0111111000010001111
3110122112200111221222121
41323032330333002033
54131443201042312
6140442032353411
712363016616224
oct1731674770217
9418480457877
10132321112207
1151131900089
122178a0a5867
13c629a2c3cb
14659387194b
153696a05707
hex1ecef3f08f

132321112207 has 4 divisors (see below), whose sum is σ = 132337134160. Its totient is φ = 132305090256.

The previous prime is 132321112201. The next prime is 132321112247. The reversal of 132321112207 is 702211123231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 702211123231 = 2579272280389.

It is a cyclic number.

It is not a de Polignac number, because 132321112207 - 23 = 132321112199 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132321112201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7998582 + ... + 8015107.

It is an arithmetic number, because the mean of its divisors is an integer number (33084283540).

Almost surely, 2132321112207 is an apocalyptic number.

132321112207 is a deficient number, since it is larger than the sum of its proper divisors (16021953).

132321112207 is an equidigital number, since it uses as much as digits as its factorization.

132321112207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16021952.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 132321112207 its reverse (702211123231), we get a palindrome (834532235438).

The spelling of 132321112207 in words is "one hundred thirty-two billion, three hundred twenty-one million, one hundred twelve thousand, two hundred seven".

Divisors: 1 8263 16013689 132321112207