Base | Representation |
---|---|
bin | 11110000101100001101001… |
… | …011111000110001111110101 |
3 | 122100111202221111221212011121 |
4 | 132011201221133012033311 |
5 | 114320422124241334101 |
6 | 1145231252342303541 |
7 | 36604612522044514 |
oct | 3605415137061765 |
9 | 570452844855147 |
10 | 132321122214901 |
11 | 39186088981a64 |
12 | 12a10878127bb1 |
13 | 58aaa9c981069 |
14 | 249653b11867b |
15 | 1046e992740a1 |
hex | 7858697c63f5 |
132321122214901 has 2 divisors, whose sum is σ = 132321122214902. Its totient is φ = 132321122214900.
The previous prime is 132321122214893. The next prime is 132321122214907. The reversal of 132321122214901 is 109412221123231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75436190530801 + 56884931684100 = 8685401^2 + 7542210^2 .
It is a cyclic number.
It is not a de Polignac number, because 132321122214901 - 23 = 132321122214893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132321122214907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160561107450 + 66160561107451.
It is an arithmetic number, because the mean of its divisors is an integer number (66160561107451).
Almost surely, 2132321122214901 is an apocalyptic number.
It is an amenable number.
132321122214901 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321122214901 is an equidigital number, since it uses as much as digits as its factorization.
132321122214901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 34.
The spelling of 132321122214901 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, one hundred twenty-two million, two hundred fourteen thousand, nine hundred one".
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