Base | Representation |
---|---|
bin | 111101100111011110… |
… | …1010111001111000011 |
3 | 110122112200200222221212 |
4 | 1323032331113033003 |
5 | 4131443212230311 |
6 | 140442034440335 |
7 | 12363020511221 |
oct | 1731675271703 |
9 | 418480628855 |
10 | 132321211331 |
11 | 51131968601 |
12 | 2178a1330ab |
13 | c629a6556a |
14 | 6593899b11 |
15 | 3696a24c8b |
hex | 1ecef573c3 |
132321211331 has 2 divisors, whose sum is σ = 132321211332. Its totient is φ = 132321211330.
The previous prime is 132321211327. The next prime is 132321211349. The reversal of 132321211331 is 133112123231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132321211331 - 22 = 132321211327 is a prime.
It is a super-2 number, since 2×1323212113312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132321211297 and 132321211306.
It is not a weakly prime, because it can be changed into another prime (132321211531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160605665 + 66160605666.
It is an arithmetic number, because the mean of its divisors is an integer number (66160605666).
Almost surely, 2132321211331 is an apocalyptic number.
132321211331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321211331 is an equidigital number, since it uses as much as digits as its factorization.
132321211331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 23.
Adding to 132321211331 its reverse (133112123231), we get a palindrome (265433334562).
The spelling of 132321211331 in words is "one hundred thirty-two billion, three hundred twenty-one million, two hundred eleven thousand, three hundred thirty-one".
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