Base | Representation |
---|---|
bin | 11110000101100001110100… |
… | …001001001101001100010011 |
3 | 122100111210101222102101021102 |
4 | 132011201310021031030103 |
5 | 114320423011030304210 |
6 | 1145231322211015015 |
7 | 36604620122650415 |
oct | 3605416411151423 |
9 | 570453358371242 |
10 | 132321301025555 |
11 | 3918616a902064 |
12 | 12a10907b9a46b |
13 | 58aaacaa29795 |
14 | 2496556b829b5 |
15 | 1046ea9ce4ea5 |
hex | 78587424d313 |
132321301025555 has 8 divisors (see below), whose sum is σ = 167142696032400. Its totient is φ = 100285617619296.
The previous prime is 132321301025497. The next prime is 132321301025569. The reversal of 132321301025555 is 555520103123231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132321301025555 - 210 = 132321301024531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 696427900040 + ... + 696427900229.
It is an arithmetic number, because the mean of its divisors is an integer number (20892837004050).
Almost surely, 2132321301025555 is an apocalyptic number.
132321301025555 is a deficient number, since it is larger than the sum of its proper divisors (34821395006845).
132321301025555 is a wasteful number, since it uses less digits than its factorization.
132321301025555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1392855800293.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 132321301025555 its reverse (555520103123231), we get a palindrome (687841404148786).
The spelling of 132321301025555 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, three hundred one million, twenty-five thousand, five hundred fifty-five".
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