Base | Representation |
---|---|
bin | 10011010000010101101… |
… | …001011110100111010011 |
3 | 11200111102222221020020112 |
4 | 103100111221132213103 |
5 | 133134420024401003 |
6 | 2451513053231535 |
7 | 164412311650043 |
oct | 23202551364723 |
9 | 4614388836215 |
10 | 1323213122003 |
11 | 470198347343 |
12 | 1945454925ab |
13 | 97a173864a6 |
14 | 480884b3723 |
15 | 24646cd23d8 |
hex | 13415a5e9d3 |
1323213122003 has 4 divisors (see below), whose sum is σ = 1324397736480. Its totient is φ = 1322028507528.
The previous prime is 1323213121889. The next prime is 1323213122069. The reversal of 1323213122003 is 3002213123231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1323213122003 - 224 = 1323196344787 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1323213122003.
It is not an unprimeable number, because it can be changed into a prime (1323213122093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592305563 + ... + 592307796.
It is an arithmetic number, because the mean of its divisors is an integer number (331099434120).
Almost surely, 21323213122003 is an apocalyptic number.
1323213122003 is a deficient number, since it is larger than the sum of its proper divisors (1184614477).
1323213122003 is a wasteful number, since it uses less digits than its factorization.
1323213122003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1184614476.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1323213122003 its reverse (3002213123231), we get a palindrome (4325426245234).
The spelling of 1323213122003 in words is "one trillion, three hundred twenty-three billion, two hundred thirteen million, one hundred twenty-two thousand, three".
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