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1323216364493 is a prime number
BaseRepresentation
bin10011010000010101110…
…101110110001111001101
311200111110020000222002202
4103100111311312033031
5133134421342130433
62451513250531245
7164412351343262
oct23202565661715
94614406028082
101323216364493
1147019a161491
12194546596b25
1397a17c5031a
1448088ab9269
1524647222ee8
hex13415d763cd

1323216364493 has 2 divisors, whose sum is σ = 1323216364494. Its totient is φ = 1323216364492.

The previous prime is 1323216364439. The next prime is 1323216364513. The reversal of 1323216364493 is 3944636123231.

Together with previous prime (1323216364439) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1057086253609 + 266130110884 = 1028147^2 + 515878^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323216364493 - 26 = 1323216364429 is a prime.

It is a super-2 number, since 2×13232163644932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323216367493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661608182246 + 661608182247.

It is an arithmetic number, because the mean of its divisors is an integer number (661608182247).

Almost surely, 21323216364493 is an apocalyptic number.

It is an amenable number.

1323216364493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323216364493 is an equidigital number, since it uses as much as digits as its factorization.

1323216364493 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1679616, while the sum is 47.

The spelling of 1323216364493 in words is "one trillion, three hundred twenty-three billion, two hundred sixteen million, three hundred sixty-four thousand, four hundred ninety-three".