Base | Representation |
---|---|
bin | 10011010000010101110… |
… | …101110110001111111111 |
3 | 11200111110020000222011121 |
4 | 103100111311312033333 |
5 | 133134421342131133 |
6 | 2451513250531411 |
7 | 164412351343363 |
oct | 23202565661777 |
9 | 4614406028147 |
10 | 1323216364543 |
11 | 47019a161527 |
12 | 194546596b67 |
13 | 97a17c50358 |
14 | 48088ab92a3 |
15 | 2464722302d |
hex | 13415d763ff |
1323216364543 has 2 divisors, whose sum is σ = 1323216364544. Its totient is φ = 1323216364542.
The previous prime is 1323216364513. The next prime is 1323216364559. The reversal of 1323216364543 is 3454636123231.
It is a strong prime.
It is an emirp because it is prime and its reverse (3454636123231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1323216364543 - 221 = 1323214267391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1323216364543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323216364513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661608182271 + 661608182272.
It is an arithmetic number, because the mean of its divisors is an integer number (661608182272).
Almost surely, 21323216364543 is an apocalyptic number.
1323216364543 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323216364543 is an equidigital number, since it uses as much as digits as its factorization.
1323216364543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 933120, while the sum is 43.
The spelling of 1323216364543 in words is "one trillion, three hundred twenty-three billion, two hundred sixteen million, three hundred sixty-four thousand, five hundred forty-three".
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