Base | Representation |
---|---|
bin | 10011010000010110001… |
… | …000110010100001111111 |
3 | 11200111110120101020120011 |
4 | 103100112020302201333 |
5 | 133134424130030142 |
6 | 2451513545204051 |
7 | 164412441504151 |
oct | 23202610624177 |
9 | 4614416336504 |
10 | 1323221330047 |
11 | 4701a1a43151 |
12 | 194548190627 |
13 | 97a18c9b516 |
14 | 4808960cad1 |
15 | 246478a4417 |
hex | 1341623287f |
1323221330047 has 2 divisors, whose sum is σ = 1323221330048. Its totient is φ = 1323221330046.
The previous prime is 1323221330009. The next prime is 1323221330063. The reversal of 1323221330047 is 7400331223231.
It is a strong prime.
It is an emirp because it is prime and its reverse (7400331223231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1323221330047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323221330077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661610665023 + 661610665024.
It is an arithmetic number, because the mean of its divisors is an integer number (661610665024).
Almost surely, 21323221330047 is an apocalyptic number.
1323221330047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323221330047 is an equidigital number, since it uses as much as digits as its factorization.
1323221330047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 1323221330047 its reverse (7400331223231), we get a palindrome (8723552553278).
The spelling of 1323221330047 in words is "one trillion, three hundred twenty-three billion, two hundred twenty-one million, three hundred thirty thousand, forty-seven".
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