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1323221330047 is a prime number
BaseRepresentation
bin10011010000010110001…
…000110010100001111111
311200111110120101020120011
4103100112020302201333
5133134424130030142
62451513545204051
7164412441504151
oct23202610624177
94614416336504
101323221330047
114701a1a43151
12194548190627
1397a18c9b516
144808960cad1
15246478a4417
hex1341623287f

1323221330047 has 2 divisors, whose sum is σ = 1323221330048. Its totient is φ = 1323221330046.

The previous prime is 1323221330009. The next prime is 1323221330063. The reversal of 1323221330047 is 7400331223231.

It is a strong prime.

It is an emirp because it is prime and its reverse (7400331223231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323221330047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323221330077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661610665023 + 661610665024.

It is an arithmetic number, because the mean of its divisors is an integer number (661610665024).

Almost surely, 21323221330047 is an apocalyptic number.

1323221330047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323221330047 is an equidigital number, since it uses as much as digits as its factorization.

1323221330047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 31.

Adding to 1323221330047 its reverse (7400331223231), we get a palindrome (8723552553278).

The spelling of 1323221330047 in words is "one trillion, three hundred twenty-three billion, two hundred twenty-one million, three hundred thirty thousand, forty-seven".