Base | Representation |
---|---|
bin | 10011010000010110010… |
… | …001010001011000000111 |
3 | 11200111110201120012121212 |
4 | 103100112101101120013 |
5 | 133134430212203133 |
6 | 2451514105002035 |
7 | 164412466424513 |
oct | 23202621213007 |
9 | 4614421505555 |
10 | 1323223553543 |
11 | 4701a3221751 |
12 | 194548a8331b |
13 | 97a195995b8 |
14 | 48089a2b143 |
15 | 24647b93148 |
hex | 13416451607 |
1323223553543 has 2 divisors, whose sum is σ = 1323223553544. Its totient is φ = 1323223553542.
The previous prime is 1323223553539. The next prime is 1323223553581. The reversal of 1323223553543 is 3453553223231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1323223553543 - 22 = 1323223553539 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1323223553543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323223583543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661611776771 + 661611776772.
It is an arithmetic number, because the mean of its divisors is an integer number (661611776772).
Almost surely, 21323223553543 is an apocalyptic number.
1323223553543 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323223553543 is an equidigital number, since it uses as much as digits as its factorization.
1323223553543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 972000, while the sum is 41.
Adding to 1323223553543 its reverse (3453553223231), we get a palindrome (4776776776774).
The spelling of 1323223553543 in words is "one trillion, three hundred twenty-three billion, two hundred twenty-three million, five hundred fifty-three thousand, five hundred forty-three".
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