Base | Representation |
---|---|
bin | 11000101001011011… |
… | …01011110110011111 |
3 | 1021011012010200220221 |
4 | 30110231223312133 |
5 | 204100000003203 |
6 | 10025012422211 |
7 | 645624506452 |
oct | 142455536637 |
9 | 37135120827 |
10 | 13232422303 |
11 | 56803a2801 |
12 | 2693617967 |
13 | 132b59b6a9 |
14 | 8d758b499 |
15 | 526a62abd |
hex | 314b6bd9f |
13232422303 has 2 divisors, whose sum is σ = 13232422304. Its totient is φ = 13232422302.
The previous prime is 13232422271. The next prime is 13232422319. The reversal of 13232422303 is 30322423231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13232422303 - 25 = 13232422271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13232422103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616211151 + 6616211152.
It is an arithmetic number, because the mean of its divisors is an integer number (6616211152).
Almost surely, 213232422303 is an apocalyptic number.
13232422303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232422303 is an equidigital number, since it uses as much as digits as its factorization.
13232422303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13232422303 its reverse (30322423231), we get a palindrome (43554845534).
The spelling of 13232422303 in words is "thirteen billion, two hundred thirty-two million, four hundred twenty-two thousand, three hundred three".
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