Base | Representation |
---|---|
bin | 11110000101101010000010… |
… | …000011110000000111001111 |
3 | 122100112122011220011211010122 |
4 | 132011222002003300013033 |
5 | 114321044043322130333 |
6 | 1145235341522455155 |
7 | 36605351562334265 |
oct | 3605520203600717 |
9 | 570478156154118 |
10 | 132330124411343 |
11 | 39189988433431 |
12 | 12a1256ab044bb |
13 | 58ab8a5a20011 |
14 | 2496b52942435 |
15 | 1047324736798 |
hex | 785a820f01cf |
132330124411343 has 2 divisors, whose sum is σ = 132330124411344. Its totient is φ = 132330124411342.
The previous prime is 132330124411339. The next prime is 132330124411351. The reversal of 132330124411343 is 343114421033231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132330124411343 - 22 = 132330124411339 is a prime.
It is a super-2 number, since 2×1323301244113432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132330124411333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66165062205671 + 66165062205672.
It is an arithmetic number, because the mean of its divisors is an integer number (66165062205672).
Almost surely, 2132330124411343 is an apocalyptic number.
132330124411343 is a deficient number, since it is larger than the sum of its proper divisors (1).
132330124411343 is an equidigital number, since it uses as much as digits as its factorization.
132330124411343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 132330124411343 its reverse (343114421033231), we get a palindrome (475444545444574).
The spelling of 132330124411343 in words is "one hundred thirty-two trillion, three hundred thirty billion, one hundred twenty-four million, four hundred eleven thousand, three hundred forty-three".
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