Base | Representation |
---|---|
bin | 10011010000011011000… |
… | …000011000011100100011 |
3 | 11200111200021002010022112 |
4 | 103100123000120130203 |
5 | 133140111032342011 |
6 | 2451530024025535 |
7 | 164414453004302 |
oct | 23203300303443 |
9 | 4614607063275 |
10 | 1323303012131 |
11 | 470234063101 |
12 | 19456b6022ab |
13 | 97a2cb9a409 |
14 | 480963d2439 |
15 | 2464eb3b58b |
hex | 1341b018723 |
1323303012131 has 2 divisors, whose sum is σ = 1323303012132. Its totient is φ = 1323303012130.
The previous prime is 1323303012127. The next prime is 1323303012173. The reversal of 1323303012131 is 1312103033231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1323303012131 - 22 = 1323303012127 is a prime.
It is a super-2 number, since 2×13233030121312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1323303012097 and 1323303012106.
It is not a weakly prime, because it can be changed into another prime (1323303012181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661651506065 + 661651506066.
It is an arithmetic number, because the mean of its divisors is an integer number (661651506066).
Almost surely, 21323303012131 is an apocalyptic number.
1323303012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323303012131 is an equidigital number, since it uses as much as digits as its factorization.
1323303012131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1323303012131 its reverse (1312103033231), we get a palindrome (2635406045362).
The spelling of 1323303012131 in words is "one trillion, three hundred twenty-three billion, three hundred three million, twelve thousand, one hundred thirty-one".
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