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13233100214 = 26616550107
BaseRepresentation
bin11000101001100000…
…10001010110110110
31021011020102010211202
430110300101112312
5204100133201324
610025035132502
7645633332045
oct142460212666
937136363752
1013233100214
115680816064
1226938a4132
13132b778119
148d76c655c
15526b488ae
hex314c115b6

13233100214 has 4 divisors (see below), whose sum is σ = 19849650324. Its totient is φ = 6616550106.

The previous prime is 13233100211. The next prime is 13233100217. The reversal of 13233100214 is 41200133231.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13233100211) and next prime (13233100217).

It is a super-2 number, since 2×132331002142 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13233100211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3308275052 + ... + 3308275055.

It is an arithmetic number, because the mean of its divisors is an integer number (4962412581).

Almost surely, 213233100214 is an apocalyptic number.

13233100214 is a deficient number, since it is larger than the sum of its proper divisors (6616550110).

13233100214 is an equidigital number, since it uses as much as digits as its factorization.

13233100214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6616550109.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13233100214 its reverse (41200133231), we get a palindrome (54433233445).

The spelling of 13233100214 in words is "thirteen billion, two hundred thirty-three million, one hundred thousand, two hundred fourteen".

Divisors: 1 2 6616550107 13233100214