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132331021300222 = 266165510650111
BaseRepresentation
bin11110000101101010110111…
…100001000111000111111110
3122100112201111101211111101021
4132011222313201013013332
5114321102412423101342
61145240010522134354
736605413032634543
oct3605526741070776
9570481441744337
10132331021300222
113918a2a8730308
1212a1277b3513ba
1358ab9b97975b4
142496bd9accbca
15104737834b567
hex785ab78471fe

132331021300222 has 4 divisors (see below), whose sum is σ = 198496531950336. Its totient is φ = 66165510650110.

The previous prime is 132331021300201. The next prime is 132331021300229. The reversal of 132331021300222 is 222003120133231.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1323310213002222 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132331021300229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33082755325054 + ... + 33082755325057.

It is an arithmetic number, because the mean of its divisors is an integer number (49624132987584).

Almost surely, 2132331021300222 is an apocalyptic number.

132331021300222 is a deficient number, since it is larger than the sum of its proper divisors (66165510650114).

132331021300222 is an equidigital number, since it uses as much as digits as its factorization.

132331021300222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66165510650113.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 132331021300222 its reverse (222003120133231), we get a palindrome (354334141433453).

The spelling of 132331021300222 in words is "one hundred thirty-two trillion, three hundred thirty-one billion, twenty-one million, three hundred thousand, two hundred twenty-two".

Divisors: 1 2 66165510650111 132331021300222