1323313244131 has 2 divisors, whose sum is σ = 1323313244132. Its totient is φ = 1323313244130.

The previous prime is 1323313244111. The next prime is 1323313244159. The reversal of 1323313244131 is 1314423133231.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1323313244131 is a prime.

It is a super-2 number, since 2×1323313244131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1323313244093 and 1323313244102.

It is not a weakly prime, because it can be changed into another prime (1323313244111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661656622065 + 661656622066.

It is an arithmetic number, because the mean of its divisors is an integer number (661656622066).

Almost surely, 2^{1323313244131} is an apocalyptic number.

1323313244131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323313244131 is an equidigital number, since it uses as much as digits as its factorization.

1323313244131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 31.

Adding to 1323313244131 its reverse (1314423133231), we get a palindrome (2637736377362).

The spelling of 1323313244131 in words is "one trillion, three hundred twenty-three billion, three hundred thirteen million, two hundred forty-four thousand, one hundred thirty-one".