132331400000013 has 4 divisors (see below), whose sum is σ = 176441866666688. Its totient is φ = 88220933333340.

The previous prime is 132331400000011. The next prime is 132331400000039. The reversal of 132331400000013 is 310000004133231.

132331400000013 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 132331400000013 - 2¹ = 132331400000011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132331400000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22055233333333 + ... + 22055233333338.

It is an arithmetic number, because the mean of its divisors is an integer number (44110466666672).

Almost surely, 2^{132331400000013} is an apocalyptic number.

It is an amenable number.

132331400000013 is a deficient number, since it is larger than the sum of its proper divisors (44110466666675).

132331400000013 is an equidigital number, since it uses as much as digits as its factorization.

132331400000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44110466666674.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 132331400000013 its reverse (310000004133231), we get a palindrome (442331404133244).

The spelling of 132331400000013 in words is "one hundred thirty-two trillion, three hundred thirty-one billion, four hundred million, thirteen", and thus it is an aban number.