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1323320014231 is a prime number
BaseRepresentation
bin10011010000011100000…
…001001111010110010111
311200111201110001220210221
4103100130001033112113
5133140124410423411
62451531432255211
7164415050346145
oct23203401172627
94614643056727
101323320014231
11470242716026
12194575241507
1397a33571127
144809877a595
1524651399071
hex1341c04f597

1323320014231 has 2 divisors, whose sum is σ = 1323320014232. Its totient is φ = 1323320014230.

The previous prime is 1323320014223. The next prime is 1323320014253. The reversal of 1323320014231 is 1324100233231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1323320014231 - 23 = 1323320014223 is a prime.

It is a super-2 number, since 2×13233200142312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1323320014196 and 1323320014205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323320024231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661660007115 + 661660007116.

It is an arithmetic number, because the mean of its divisors is an integer number (661660007116).

Almost surely, 21323320014231 is an apocalyptic number.

1323320014231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323320014231 is an equidigital number, since it uses as much as digits as its factorization.

1323320014231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1323320014231 its reverse (1324100233231), we get a palindrome (2647420247462).

The spelling of 1323320014231 in words is "one trillion, three hundred twenty-three billion, three hundred twenty million, fourteen thousand, two hundred thirty-one".