Base | Representation |
---|---|
bin | 111101100111110011… |
… | …1010110111011100101 |
3 | 110122120110102022012021 |
4 | 1323033213112323211 |
5 | 4132004022021013 |
6 | 140443110423141 |
7 | 12363213211651 |
oct | 1731747267345 |
9 | 418513368167 |
10 | 132332220133 |
11 | 511380a7693 |
12 | 21791961ab1 |
13 | c62c11b349 |
14 | 6595123a61 |
15 | 369799ba8d |
hex | 1ecf9d6ee5 |
132332220133 has 4 divisors (see below), whose sum is σ = 132333041068. Its totient is φ = 132331399200.
The previous prime is 132332220127. The next prime is 132332220149. The reversal of 132332220133 is 331022233231.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 331022233231 = 13309 ⋅24872059.
It can be written as a sum of positive squares in 2 ways, for example, as 117743687044 + 14588533089 = 343138^2 + 120783^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132332220133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132332220098 and 132332220107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132332224133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79968 + ... + 520633.
It is an arithmetic number, because the mean of its divisors is an integer number (33083260267).
Almost surely, 2132332220133 is an apocalyptic number.
It is an amenable number.
132332220133 is a deficient number, since it is larger than the sum of its proper divisors (820935).
132332220133 is an equidigital number, since it uses as much as digits as its factorization.
132332220133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 820934.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 132332220133 its reverse (331022233231), we get a palindrome (463354453364).
The spelling of 132332220133 in words is "one hundred thirty-two billion, three hundred thirty-two million, two hundred twenty thousand, one hundred thirty-three".
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