Search a number
-
+
132336152341957 is a prime number
BaseRepresentation
bin11110000101101111101001…
…010110011110110111000101
3122100120012201222210102102001
4132011233221112132313011
5114321143414444420312
61145242220014145301
736605654136032104
oct3605575126366705
9570505658712361
10132336152341957
11391914a1000973
1212a137717b2231
1358ac326817b75
14249716534203b
151047578a3a057
hex785be959edc5

132336152341957 has 2 divisors, whose sum is σ = 132336152341958. Its totient is φ = 132336152341956.

The previous prime is 132336152341901. The next prime is 132336152342059. The reversal of 132336152341957 is 759143251633231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121933405183716 + 10402747158241 = 11042346^2 + 3225329^2 .

It is a cyclic number.

It is not a de Polignac number, because 132336152341957 - 231 = 132334004858309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132336152341898 and 132336152341907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132336152041957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66168076170978 + 66168076170979.

It is an arithmetic number, because the mean of its divisors is an integer number (66168076170979).

Almost surely, 2132336152341957 is an apocalyptic number.

It is an amenable number.

132336152341957 is a deficient number, since it is larger than the sum of its proper divisors (1).

132336152341957 is an equidigital number, since it uses as much as digits as its factorization.

132336152341957 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12247200, while the sum is 55.

The spelling of 132336152341957 in words is "one hundred thirty-two trillion, three hundred thirty-six billion, one hundred fifty-two million, three hundred forty-one thousand, nine hundred fifty-seven".