Base | Representation |
---|---|
bin | 1100000010010100100001… |
… | …1111110111110010111101 |
3 | 1201212011021221122100022202 |
4 | 3000211020133313302331 |
5 | 3213311223200203113 |
6 | 44051342010521245 |
7 | 2534061055444220 |
oct | 300451037676275 |
9 | 51764257570282 |
10 | 13234010553533 |
11 | 424256aa47180 |
12 | 1598a0b436225 |
13 | 74cc67217883 |
14 | 33a75b0515b7 |
15 | 17e3a8892258 |
hex | c09487f7cbd |
13234010553533 has 16 divisors (see below), whose sum is σ = 17031789035520. Its totient is φ = 9979563884400.
The previous prime is 13234010553457. The next prime is 13234010553611. The reversal of 13234010553533 is 33535501043231.
It is not a de Polignac number, because 13234010553533 - 218 = 13234010291389 is a prime.
It is a super-3 number, since 3×132340105535333 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13234010552533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2772098693 + ... + 2772103466.
It is an arithmetic number, because the mean of its divisors is an integer number (1064486814720).
Almost surely, 213234010553533 is an apocalyptic number.
It is an amenable number.
13234010553533 is a deficient number, since it is larger than the sum of its proper divisors (3797778481987).
13234010553533 is a wasteful number, since it uses less digits than its factorization.
13234010553533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5544202208.
The product of its (nonzero) digits is 243000, while the sum is 38.
Adding to 13234010553533 its reverse (33535501043231), we get a palindrome (46769511596764).
The spelling of 13234010553533 in words is "thirteen trillion, two hundred thirty-four billion, ten million, five hundred fifty-three thousand, five hundred thirty-three".
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