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13234010553533 = 711315544202159
BaseRepresentation
bin1100000010010100100001…
…1111110111110010111101
31201212011021221122100022202
43000211020133313302331
53213311223200203113
644051342010521245
72534061055444220
oct300451037676275
951764257570282
1013234010553533
11424256aa47180
121598a0b436225
1374cc67217883
1433a75b0515b7
1517e3a8892258
hexc09487f7cbd

13234010553533 has 16 divisors (see below), whose sum is σ = 17031789035520. Its totient is φ = 9979563884400.

The previous prime is 13234010553457. The next prime is 13234010553611. The reversal of 13234010553533 is 33535501043231.

It is not a de Polignac number, because 13234010553533 - 218 = 13234010291389 is a prime.

It is a super-3 number, since 3×132340105535333 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13234010552533) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2772098693 + ... + 2772103466.

It is an arithmetic number, because the mean of its divisors is an integer number (1064486814720).

Almost surely, 213234010553533 is an apocalyptic number.

It is an amenable number.

13234010553533 is a deficient number, since it is larger than the sum of its proper divisors (3797778481987).

13234010553533 is a wasteful number, since it uses less digits than its factorization.

13234010553533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5544202208.

The product of its (nonzero) digits is 243000, while the sum is 38.

Adding to 13234010553533 its reverse (33535501043231), we get a palindrome (46769511596764).

The spelling of 13234010553533 in words is "thirteen trillion, two hundred thirty-four billion, ten million, five hundred fifty-three thousand, five hundred thirty-three".

Divisors: 1 7 11 31 77 217 341 2387 5544202159 38809415113 60986223749 171870266929 426903566243 1203091868503 1890572936219 13234010553533