Base | Representation |
---|---|
bin | 1100000010010100101010… |
… | …0100100100110110111111 |
3 | 1201212011101101002201220212 |
4 | 3000211022210210312333 |
5 | 3213311311101403434 |
6 | 44051345252303035 |
7 | 2534061660232601 |
oct | 300451244446677 |
9 | 51764341081825 |
10 | 13234045341119 |
11 | 4242588647649 |
12 | 1598a1b011a7b |
13 | 74cc714a7a45 |
14 | 33a761909171 |
15 | 17e3ab9648ce |
hex | c094a924dbf |
13234045341119 has 2 divisors, whose sum is σ = 13234045341120. Its totient is φ = 13234045341118.
The previous prime is 13234045341089. The next prime is 13234045341157. The reversal of 13234045341119 is 91114354043231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13234045341119 is a prime.
It is a super-2 number, since 2×132340453411192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13234045341619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617022670559 + 6617022670560.
It is an arithmetic number, because the mean of its divisors is an integer number (6617022670560).
Almost surely, 213234045341119 is an apocalyptic number.
13234045341119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13234045341119 is an equidigital number, since it uses as much as digits as its factorization.
13234045341119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 13234045341119 in words is "thirteen trillion, two hundred thirty-four billion, forty-five million, three hundred forty-one thousand, one hundred nineteen".
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