Search a number
-
+
1323434343169 is a prime number
BaseRepresentation
bin10011010000100010110…
…101010111101100000001
311200112000102012102122001
4103100202311113230001
5133140343142440134
62451551034544001
7164420636210521
oct23204265275401
94615012172561
101323434343169
114702a1204054
121945a7598001
1397a511609a3
14480a9a1b681
152465b42e414
hex13422d57b01

1323434343169 has 2 divisors, whose sum is σ = 1323434343170. Its totient is φ = 1323434343168.

The previous prime is 1323434343167. The next prime is 1323434343239. The reversal of 1323434343169 is 9613434343231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 784795776769 + 538638566400 = 885887^2 + 733920^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323434343169 - 21 = 1323434343167 is a prime.

It is a super-2 number, since 2×13234343431692 (a number of 25 digits) contains 22 as substring.

Together with 1323434343167, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1323434343163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661717171584 + 661717171585.

It is an arithmetic number, because the mean of its divisors is an integer number (661717171585).

Almost surely, 21323434343169 is an apocalyptic number.

It is an amenable number.

1323434343169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323434343169 is an equidigital number, since it uses as much as digits as its factorization.

1323434343169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1679616, while the sum is 46.

The spelling of 1323434343169 in words is "one trillion, three hundred twenty-three billion, four hundred thirty-four million, three hundred forty-three thousand, one hundred sixty-nine".