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132354054040457 is a prime number
BaseRepresentation
bin11110000110000000010100…
…011000000010101110001001
3122100121220221120222221010102
4132012000110120002232021
5114321442100313243312
61145254340225455145
736610156561664654
oct3606002430025611
9570556846887112
10132354054040457
1139199048051a17
1212a17128aa14b5
1358b0c1a57aa82
142497d82aa089b
151047c75476ec2
hex786014602b89

132354054040457 has 2 divisors, whose sum is σ = 132354054040458. Its totient is φ = 132354054040456.

The previous prime is 132354054040391. The next prime is 132354054040501. The reversal of 132354054040457 is 754040450453231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128255194650361 + 4098859390096 = 11324981^2 + 2024564^2 .

It is a cyclic number.

It is not a de Polignac number, because 132354054040457 - 216 = 132354053974921 is a prime.

It is not a weakly prime, because it can be changed into another prime (132354054045457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66177027020228 + 66177027020229.

It is an arithmetic number, because the mean of its divisors is an integer number (66177027020229).

Almost surely, 2132354054040457 is an apocalyptic number.

It is an amenable number.

132354054040457 is a deficient number, since it is larger than the sum of its proper divisors (1).

132354054040457 is an equidigital number, since it uses as much as digits as its factorization.

132354054040457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032000, while the sum is 47.

The spelling of 132354054040457 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, fifty-four million, forty thousand, four hundred fifty-seven".