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132355220314315 = 526471044062863
BaseRepresentation
bin11110000110000001011001…
…111001000001100011001011
3122100122000221212112210002111
4132012001121321001203023
5114322001442400024230
61145255052051043151
736610230513105205
oct3606013171014313
9570560855483074
10132355220314315
1139199596412809
1212a173b35a04b7
1358b107509424b
142498053931775
151047ce2a4e92a
hex786059e418cb

132355220314315 has 4 divisors (see below), whose sum is σ = 158826264377184. Its totient is φ = 105884176251448.

The previous prime is 132355220314297. The next prime is 132355220314319. The reversal of 132355220314315 is 513413022553231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132355220314315 - 25 = 132355220314283 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132355220314319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13235522031427 + ... + 13235522031436.

It is an arithmetic number, because the mean of its divisors is an integer number (39706566094296).

Almost surely, 2132355220314315 is an apocalyptic number.

132355220314315 is a deficient number, since it is larger than the sum of its proper divisors (26471044062869).

132355220314315 is an equidigital number, since it uses as much as digits as its factorization.

132355220314315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26471044062868.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 132355220314315 its reverse (513413022553231), we get a palindrome (645768242867546).

The spelling of 132355220314315 in words is "one hundred thirty-two trillion, three hundred fifty-five billion, two hundred twenty million, three hundred fourteen thousand, three hundred fifteen".

Divisors: 1 5 26471044062863 132355220314315