Base | Representation |
---|---|
bin | 11110000110000001101100… |
… | …100010010101111001000111 |
3 | 122100122001202200011201222202 |
4 | 132012001230202111321013 |
5 | 114322003112440313211 |
6 | 1145255143103545115 |
7 | 36610241332044134 |
oct | 3606015442257107 |
9 | 570561680151882 |
10 | 132355533135431 |
11 | 39199736a53961 |
12 | 12a174802bb19b |
13 | 58b10c4b309b8 |
14 | 24980832c158b |
15 | 1047d1024253b |
hex | 78606c895e47 |
132355533135431 has 2 divisors, whose sum is σ = 132355533135432. Its totient is φ = 132355533135430.
The previous prime is 132355533135391. The next prime is 132355533135503. The reversal of 132355533135431 is 134531335553231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132355533135431 is a prime.
It is a super-2 number, since 2×1323555331354312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132351533135431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66177766567715 + 66177766567716.
It is an arithmetic number, because the mean of its divisors is an integer number (66177766567716).
Almost surely, 2132355533135431 is an apocalyptic number.
132355533135431 is a deficient number, since it is larger than the sum of its proper divisors (1).
132355533135431 is an equidigital number, since it uses as much as digits as its factorization.
132355533135431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3645000, while the sum is 47.
Adding to 132355533135431 its reverse (134531335553231), we get a palindrome (266886868688662).
The spelling of 132355533135431 in words is "one hundred thirty-two trillion, three hundred fifty-five billion, five hundred thirty-three million, one hundred thirty-five thousand, four hundred thirty-one".
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