Base | Representation |
---|---|
bin | 11110000110001010101000… |
… | …111000001001101111110011 |
3 | 122100122222112212120100122220 |
4 | 132012022220320021233303 |
5 | 114322132244131423103 |
6 | 1145303412002132123 |
7 | 36611031310112064 |
oct | 3606125070115763 |
9 | 570588485510586 |
10 | 132365135420403 |
11 | 391a2814213766 |
12 | 12a19300051043 |
13 | 58b1c952c9922 |
14 | 24987146b656b |
15 | 10481c323dc53 |
hex | 7862a8e09bf3 |
132365135420403 has 8 divisors (see below), whose sum is σ = 180791404476816. Its totient is φ = 86091144988800.
The previous prime is 132365135420359. The next prime is 132365135420491. The reversal of 132365135420403 is 304024531563231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132365135420403 - 212 = 132365135416307 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132365135420603) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 538069656058 + ... + 538069656303.
It is an arithmetic number, because the mean of its divisors is an integer number (22598925559602).
Almost surely, 2132365135420403 is an apocalyptic number.
132365135420403 is a deficient number, since it is larger than the sum of its proper divisors (48426269056413).
132365135420403 is a wasteful number, since it uses less digits than its factorization.
132365135420403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1076139312405.
The product of its (nonzero) digits is 777600, while the sum is 42.
Adding to 132365135420403 its reverse (304024531563231), we get a palindrome (436389666983634).
The spelling of 132365135420403 in words is "one hundred thirty-two trillion, three hundred sixty-five billion, one hundred thirty-five million, four hundred twenty thousand, four hundred three".
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