Base | Representation |
---|---|
bin | 11110000110001010101000… |
… | …111000001001110010111011 |
3 | 122100122222112212120100221022 |
4 | 132012022220320021302323 |
5 | 114322132244131424403 |
6 | 1145303412002133055 |
7 | 36611031310112501 |
oct | 3606125070116273 |
9 | 570588485510838 |
10 | 132365135420603 |
11 | 391a2814213928 |
12 | 12a1930005118b |
13 | 58b1c952c9a47 |
14 | 24987146b6671 |
15 | 10481c323dd38 |
hex | 7862a8e09cbb |
132365135420603 has 2 divisors, whose sum is σ = 132365135420604. Its totient is φ = 132365135420602.
The previous prime is 132365135420593. The next prime is 132365135420663. The reversal of 132365135420603 is 306024531563231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132365135420603 - 222 = 132365131226299 is a prime.
It is not a weakly prime, because it can be changed into another prime (132365135420663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66182567710301 + 66182567710302.
It is an arithmetic number, because the mean of its divisors is an integer number (66182567710302).
Almost surely, 2132365135420603 is an apocalyptic number.
132365135420603 is a deficient number, since it is larger than the sum of its proper divisors (1).
132365135420603 is an equidigital number, since it uses as much as digits as its factorization.
132365135420603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1166400, while the sum is 44.
Adding to 132365135420603 its reverse (306024531563231), we get a palindrome (438389666983834).
The spelling of 132365135420603 in words is "one hundred thirty-two trillion, three hundred sixty-five billion, one hundred thirty-five million, four hundred twenty thousand, six hundred three".
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